21j-22j^2=-j^3

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Solution for 21j-22j^2=-j^3 equation:


Simplifying
21j + -22j2 = -1j3

Solving
21j + -22j2 = -1j3

Solving for variable 'j'.

Combine like terms: -1j3 + j3 = 0
21j + -22j2 + j3 = 0

Factor out the Greatest Common Factor (GCF), 'j'.
j(21 + -22j + j2) = 0

Factor a trinomial.
j((1 + -1j)(21 + -1j)) = 0

Subproblem 1

Set the factor 'j' equal to zero and attempt to solve: Simplifying j = 0 Solving j = 0 Move all terms containing j to the left, all other terms to the right. Simplifying j = 0

Subproblem 2

Set the factor '(1 + -1j)' equal to zero and attempt to solve: Simplifying 1 + -1j = 0 Solving 1 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1j = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1j = 0 + -1 -1j = 0 + -1 Combine like terms: 0 + -1 = -1 -1j = -1 Divide each side by '-1'. j = 1 Simplifying j = 1

Subproblem 3

Set the factor '(21 + -1j)' equal to zero and attempt to solve: Simplifying 21 + -1j = 0 Solving 21 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-21' to each side of the equation. 21 + -21 + -1j = 0 + -21 Combine like terms: 21 + -21 = 0 0 + -1j = 0 + -21 -1j = 0 + -21 Combine like terms: 0 + -21 = -21 -1j = -21 Divide each side by '-1'. j = 21 Simplifying j = 21

Solution

j = {0, 1, 21}

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